For the following reaction,?

the formula for the limiting reagent:

0.435 moles N2 (2 mole NO/ 1 mole N2)= 0.87 moles NO

The formula for excess reagent:

0.464 moles O2 (2 moles NO/ 1 mole O2)= 0.92 moles NO

The limiting reagent is what limits you from using more than what you can in order to make the product. The limiting reagent is the substance that produces the fewest moles of the product, in this case, N2 gas is the limiting reagent producing 0.87 moles of nitrogen monoxide and O2 gas will be in excess.

The equation of the reaction :
N₂(g) + O₂(g) → 2NO(g)

According to the equation, 1 mole of N₂ reacts with 1 mole of O₂.
As (Number of moles of O₂) > (Number of moles of N₂)
O₂ is in excess.
The limiting reactant is N₂.

According to the equation, the consumption of 1 mole of N₂ gives 2 moles of NO.
Maximum number of moles of N₂ reacted = 0.435 mol
Maximum number of moles of NO formed = 0.435 × 2 = 0.870 mol