設xyz不等於0，且3yz=6xz=5xy，[1] 球x:y:z=
[2]又x、y、z的最小公倍數為120，則x+y+z的值
大大請幫幫小弟解題目 跪求?
2016-04-26 1:29 pm
回答 (2)
2016-04-26 2:46 pm
✔ 最佳答案
1 同除xyz得 3/x=6/y=5/z令其等於1,則 x=3,y=6,z=5, x:y:z=3:6:52 x=3r,y=6r,z=5r {x,y,z]=30r=120, r=4
x=12,y=24,z=20, x+y+z= 56
2016-04-27 4:58 am
[1]
3yz=6xz
2x=y
10x=5y
6xz=5xy
5y=6z
10x=5y=6z
x:y:z=30:60:18
x:y:z=5:10:3
[2]
x=5*120 /(5+10+3)=100/3
y=10*120 /(5+10+3)=200/3
z=3*120 /(5+10+3)=20
x+y+z
=100/3 +200/3 +20
=20
3yz=6xz
2x=y
10x=5y
6xz=5xy
5y=6z
10x=5y=6z
x:y:z=30:60:18
x:y:z=5:10:3
[2]
x=5*120 /(5+10+3)=100/3
y=10*120 /(5+10+3)=200/3
z=3*120 /(5+10+3)=20
x+y+z
=100/3 +200/3 +20
=20
收錄日期: 2021-04-18 14:47:19
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160426052911AAf70A3