I'm confused on my chem work?
2016-04-22 8:42 pm
How many kilojoules of heat are absorbed when 1.2 g of chloroethane (C2H5Cl) vaporizes at its normal boiling point? For C2H5Cl, ΔHvap = 24.7 kJ/mol
回答 (1)
2016-04-22 8:52 pm
Molar mass of C₂H₅Cl = 12×2 + 1×5 + 35.5 = 64.5 g/mol
ΔHvap = 24.7 kJ/mol means :
24.7 kJ of heat are absorbed when 1 mol of C₂H₅Cl vaporizes.
Thus, 24.7 kJ of heat are absorbed when 64.5 g of C₂H₅Cl vaporizes.
Heat absorbed when 12 g of C₂H₅Cl vaporizes
= 24.7 × (12/64.5) kJ
= 4.60 kJ
ΔHvap = 24.7 kJ/mol means :
24.7 kJ of heat are absorbed when 1 mol of C₂H₅Cl vaporizes.
Thus, 24.7 kJ of heat are absorbed when 64.5 g of C₂H₅Cl vaporizes.
Heat absorbed when 12 g of C₂H₅Cl vaporizes
= 24.7 × (12/64.5) kJ
= 4.60 kJ
收錄日期: 2021-04-18 14:48:19
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