x^2 + 4x + 4 = 0
x^2 + x = 0
x^2 - 1 = 0
Which of the following equations has only one solution?
2016-04-20 4:41 pm
回答 (5)
2016-04-20 7:03 pm
Ignore me.
2016-04-20 5:14 pm
One solution only:
x^2 + 4x + 4 = 0
x = -2
Two solutions:
1).
x^2 + x = 0
x = -1, 0
2).
x^2 - 1 = 0
x = -1, 1
x^2 + 4x + 4 = 0
x = -2
Two solutions:
1).
x^2 + x = 0
x = -1, 0
2).
x^2 - 1 = 0
x = -1, 1
2016-04-20 5:02 pm
x^2 + 4x + 4 = 0
(x + 2)^2 = 0
x + 2 = 0
x = -2 Is the only solution.
The other two equations have two solutions.
(x + 2)^2 = 0
x + 2 = 0
x = -2 Is the only solution.
The other two equations have two solutions.
2016-04-20 4:46 pm
2016-04-20 4:42 pm
dinka
收錄日期: 2021-04-25 17:12:59
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https://hk.answers.yahoo.com/question/index?qid=20160420084100AAtlAJB