更新1:
z= ____________ ? Proportion=___________?
For a normal distribution with a mean of µ= 135.50 and o = 24.35, find each of the following probabilities. M ≥ 124.62, n=9?
回答 (2)
2016-04-15 12:45 pm
Xbar denotes M
z = (Xbar - Mu) / (SD/sqrt n)
z = (124.62 - 135) / (24.35/sqrt 9) = - 1.28
Required probability or proportion = P(Xbar >/= 124.62)
= P(z >/= - 1.28)
= 1 - P(z < - 1.28)
= 1 - 0.1003
= 0.8997
z = (Xbar - Mu) / (SD/sqrt n)
z = (124.62 - 135) / (24.35/sqrt 9) = - 1.28
Required probability or proportion = P(Xbar >/= 124.62)
= P(z >/= - 1.28)
= 1 - P(z < - 1.28)
= 1 - 0.1003
= 0.8997
2016-04-14 4:41 am
µ= 135.50 and o = 24.35
---> µ ample= 135.50 and o sample = 24.35/3=8.12
z = (x - µ)/8.12=...
proportion , need a calculator or a normal distribution table
---> µ ample= 135.50 and o sample = 24.35/3=8.12
z = (x - µ)/8.12=...
proportion , need a calculator or a normal distribution table
收錄日期: 2021-04-21 18:00:56
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160413201143AAl2aWQ