Math2 Binomial & Poisson Distributions http://postimg.org/image/6mxctnwld/?

2016-04-12 5:13 pm

回答 (1)

2016-04-14 5:26 am
1a)
P(X=4)
=e^(-2) *(2^4)/4!
=0.0902
1b)
P(X>3)
=1-P(X=0)-P(X=1)-P(X=2)-P(X=3)
=1-e^(-6.2) *(6.2^0)/0!-e^(-6.2) *(6.2^1)/1!-e^(-6.2) *(6.2^2)/2!-e^(-6.2) *(6.2^3)/3!
=0.866
1c)
P(X<3 or X=3)
=P(X=0)+P(X=1)+P(X=2)+P(X=3)
=e^(-3.3) *(3.3^0)/0!+e^(-3.3) *(3.3^1)/1!+e^(-3.3) *(3.3^2)/2!+e^(-3.3) *(3.3^3)/3!
=0.580

2
P(X>1)
=1-P(X=0)-P(X=1)
=1-e^(-1.14) *(1.14^0)/0!+e^(-1.14) *(1.14^1)/1!
=0.316

3a
P(X>5)
=1-P(X=0)-P(X=1)-P(X=2)-P(X=3)-P(X=4)-P(X=5)
=1-e^(-3.4) *(3.4^0)/0!-e^(-3.4) *(3.4^1)/1!-e^(-3.4) *(3.4^2)/2!-e^(-3.4) *(3.4^3)/3!-e^(-3.4) *(3.4^4)/4!-e^(-3.4) *(3.4^5)/5!
=0.256
3b
x 0 1 2 3 4 5 >5
$-100 -40 20 80 140 200 200
3c
per day=(20+80+140+200+200)/7=91


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