math Binomial & Poisson Distributions
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回答 (1)
1
Bi~(5,0.3)
a)
P(X=4)
=(5C4)(0.3)^4 (1-0.3)
=0.02835
b)
P(X>1)
=1-P(X=1)-P(X=0)
=1-(5C1)(0.3) (1-0.3)^4 -(1-0.3)^5
=0.47178
c)
P(X=4 or X>4)
=0.02835+0.3^5
=0.03078
2
Bi~(6,0.01)
a
P(X=0)
=(6C0)(0.01)^0 (1-0.01)^6
=0.941
b
P(X=2)
=(6C2)(0.01)^2 (1-0.01)^(6-2)
=0.00144
c
P(X>1)
=1-P(X=0)-P(X=1)
=1-0.941-(6C1)(0.01)(1-0.01)^5
=0.00146
3
Bi(8,1/6)
a
x=0,P(X=x)=0.233
x=1,P(X=x)=0.372
x=2,P(X=x)=0.260
x=3,P(X=x)=0.104
x=4,P(X=x)=0.0260
x=5,P(X=x)=0.00417
x=6,P(X=x)=4.17*10^-4
x=7,P(X=x)=2.38*10^-5
x=8,P(X=x)=5.95*10^-7
b
P(X>4)
=P(X=5)+P(X=6)+P(X=7)+P(X=8)
=0.00417+4.17*10^-4+2.38*10^-5+5.95*10^-7
=0.00461
c
P(X=0 or X>0)
=1
收錄日期: 2021-04-18 14:51:24
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