更新1:
(b) evaluate int(0 to 1) lnx dx
integration problem?
回答 (1)
2016-04-10 5:04 am
a)
int(0 to 3) 1/(x-1) dx
=In|x-1| |0 to 3
=In|3-1| - In|0-1|
=In 2 -0
=In 2
b)
int(0 to 1) lnx dx
=x In x -x |0 to 1
=In 1 -1 -0 In 0 -0
=In 1 -1
int(0 to 3) 1/(x-1) dx
=In|x-1| |0 to 3
=In|3-1| - In|0-1|
=In 2 -0
=In 2
b)
int(0 to 1) lnx dx
=x In x -x |0 to 1
=In 1 -1 -0 In 0 -0
=In 1 -1
收錄日期: 2021-04-18 14:43:49
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160409082422AAcYj67