1.(4x+7)/{[(x-1)^2](x+3)}
2.(6u-6)/(u^2-2u+6)^2
請問這幾題積分怎麼解？
2016-04-09 1:55 pm
回答 (2)
2016-04-09 6:32 pm
2016-04-19 4:22 am
1.
積分(4x+7)/{[(x-1)^2](x+3)} dx
=[44+(5-5x)log(x-1)+(5x-5)lod(3+x)]/(16-16x) +C
2.
積分(6u-6)/(u^2-2u+6)^2
=-3/(u^2 -2u+6) +C
積分(4x+7)/{[(x-1)^2](x+3)} dx
=[44+(5-5x)log(x-1)+(5x-5)lod(3+x)]/(16-16x) +C
2.
積分(6u-6)/(u^2-2u+6)^2
=-3/(u^2 -2u+6) +C
收錄日期: 2021-04-18 14:42:29
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160409055503AAwcscw