How to find the normal to the plane r = (3,-6,8) + t(4,2,1) + s(-4,3,-2)?
回答 (1)
2016-03-30 12:39 am
Take cross product of the two vectors parallel to plane:
< 4, 2, 1 > × < −4, 2, −2 > = < −6, 4, 16 >
So normal can be any vector parallel to < −6, 4, 16 >
N = < 3, −2, −8 >
收錄日期: 2021-04-21 17:43:16
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160329162544AADV6Go