A 560 mL sample of a gas at 335 ∘C and 1.20 atm is cooled at constant pressure until its volume becomes 450 mL What is the final gas temp?
回答 (1)
2016-03-28 4:40 pm
At constant P :
V₁ = 560 mL, T₁ = (273 + 335) K = 608 K
V₂ = 450 mL, T₂ = ? K
V₁/T₁ = V₂/T₂
T₂ = V₂T₁/V₁ = 450 × 608 / 560 = 489 K
Final temperature = 489 K (or 216°C)
V₁ = 560 mL, T₁ = (273 + 335) K = 608 K
V₂ = 450 mL, T₂ = ? K
V₁/T₁ = V₂/T₂
T₂ = V₂T₁/V₁ = 450 × 608 / 560 = 489 K
Final temperature = 489 K (or 216°C)
收錄日期: 2021-04-18 14:40:58
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