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44.
Median = 3m - 5
Standard Deviation = 3s
Inter - Quartile Range = 3q

∴ C.

45.
Let A = {a,b,c,d,e} and B = {a,b,c,d,e,x} and assume a ≤ b ≤ c ≤ d ≤ e

The mean of A must not be the less than a or greater than e

The mean of B = (a + b + c + d + e + x)/6 = (5x + x)/6 = x

∵ the mean of B = the mean of A
The standard deviation of A = √ {[(a - x̅)² + (b - x̅)² + (c - x̅)² + (d - x̅)² + (e - x̅)²]/5}
The standard deviation of B
= √ {[(a - x̅)² + (b - x̅)² + (c - x̅)² + (d - x̅)² + (e - x̅)² + (x̅ - x̅)²]/6}
= √ {[(a - x̅)² + (b - x̅)² + (c - x̅)² + (d - x̅)² + (e - x̅)²]/6}
The standard deviation of B must be less than the standard deviation of A

∴ B. I and II only