I have to calculate the concentration of the Cu2+ ion for 4 different solutions. The information I'm given for the first one is:
mL of 0.0500M CuSO4 = 0.50
mL of deionized H2O = 9.50
What is the molarity of the [Cu2+] ion? Please show methods!
How to calculate the concentration of Cu2+ in solutions when given volumes?
2016-03-28 2:48 am
回答 (1)
2016-03-28 3:12 am
Number of moles of CuSO₄, n = MV = 0.0500 × 0.50 = 0.025 mmol
Volume of the solution, V = 0.5 + 9.5 = 10.0 mL
Molarity of CuSO₄ = n/V = 0.025/10 = 0.25 mol/L
1 mole of CuSO₄ dissociates to give 1 mole of Cu²⁺ ion.
Molarity of CuSO₄ = Molarity of Cu²⁺ ion = 0.25 mol/L
Volume of the solution, V = 0.5 + 9.5 = 10.0 mL
Molarity of CuSO₄ = n/V = 0.025/10 = 0.25 mol/L
1 mole of CuSO₄ dissociates to give 1 mole of Cu²⁺ ion.
Molarity of CuSO₄ = Molarity of Cu²⁺ ion = 0.25 mol/L
收錄日期: 2021-04-18 14:40:49
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160327184818AAyeewp