"Find the limit, use L'Hospital if needed"..
Limit x-> infinity. x^3*e^-4x
Calculus HELP!!! ASAP?
2016-03-25 2:38 am
回答 (1)
2016-03-25 2:40 am
lim x^3 e^(-4x) =
x-> ∞
lim x^3/e^(4x) =... now use L'Hopital's rule
x-> ∞
lim 3x^2/(4e^(4x)) = ...use L'Hopital's rule again
x-> ∞
lim 6x/(16e^(4x)) = ...use L'Hopital's rule again
x-> ∞
lim 6/(64e^(4x)) = 0
x-> ∞
x-> ∞
lim x^3/e^(4x) =... now use L'Hopital's rule
x-> ∞
lim 3x^2/(4e^(4x)) = ...use L'Hopital's rule again
x-> ∞
lim 6x/(16e^(4x)) = ...use L'Hopital's rule again
x-> ∞
lim 6/(64e^(4x)) = 0
x-> ∞
收錄日期: 2021-05-01 20:32:31
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https://hk.answers.yahoo.com/question/index?qid=20160324183802AAiEQFY