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Consider the following reaction:
Fe₂O₃(s) + 3CO(g) → 2Fe(s) + 3CO₂(g)
Referring to the production of Fe information above: When 2 moles of Fe2O3 are reacted with 3 moles of CO, how many moles of Fe will be formed?

Refer to the equation.
Mole ratio Fe₂O₃ : CO : Fe = 1 : 3 : 2

If 2 moles of Fe₂O₃ completely reacts :
No. of moles of CO needed = 2 × 3 = 6 mol > 3 mol
Hence, CO is the limiting reactant (completely reacts),
and Fe₂O₃ is in excess.

No. of moles of CO reacts = 3 mol
No. of moles of Fe formed = 3 × (2/3) = 4 mol