Find equations of the tangent plane and normal line to the surface x=5y^2+5z^2−259 at the point (6, -7, -2)?
回答 (1)
2016-03-21 10:28 am
✔ 最佳答案
Let f(x,y,z) = x - 5y^2 - 5z^2 + 259 = 0gradient of f = i - 10y*j - 10z*k
gradient of f at (6, -7, -2) = i + 70j + 20k
tangent plane is
1(x-6) + 70(y+7) + 20(z+2) = 0
x + 70y + 20z = - 524 ..... Ans
normal line is
x = 6 + t , y = -7 + 70t , z = -2 + 20t ..... Ans
收錄日期: 2021-05-02 14:08:52
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