The equation 6xz2+yz+4xy−7z2=4 defines z as a function of x and near the point (x,y,z)=(1,1,1). The values of ∂z/∂y at the same point is a)10 b)8 c)3 d)5 e)12
if you could walk me through that would be awesome!
CALCULUS QUESTION: The equation 6xz^2+yz+4xy-7z^2 defines z as a function of x and y.....?
2016-03-18 1:54 am
回答 (1)
2016-03-18 9:29 am
✔ 最佳答案
6xz^2 + yz + 4xy - 7z^2 = 4∂( 6xz^2 + yz + 4xy - 7z^2 ) / ∂y = ∂4 / ∂y
12xzu + z + yu + 4x - 14zu = 0 , where u = ∂z/∂y
Substitute (x,y,z) = (1,1,1) , we get
12u + 1 + u + 4 - 14u = 0
u = 5
Ans: d
收錄日期: 2021-05-02 14:10:33
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