2Bi + 3HPbO2-+ 3H2O =3Pb + 2Bi(OH)3+ 3OH-
name of the element oxidized:
name of the element reduced:
formula of the oxidizing agent:
formula of the reducing agent:
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2016-03-17 10:31 am
回答 (1)
2016-03-17 10:59 am
2Bi + 3HPbO₂⁻ + 3H₂O ⇌ 3Pb + 2Bi(OH)₃+ 3OH⁻
Name of the element oxidized: bismuth
The oxidation number of Bi increases from 0 (in Bi) to +3 (in Bi(OH)₃).
Name of the element reduced: lead
The oxidation number of Pb decreases from +2 (in HPbO₂⁻) to 0 (in Pb).
Formula of the oxidizing agent: HPbO₂⁻
Formula of the reducing agent: Bi
Name of the element oxidized: bismuth
The oxidation number of Bi increases from 0 (in Bi) to +3 (in Bi(OH)₃).
Name of the element reduced: lead
The oxidation number of Pb decreases from +2 (in HPbO₂⁻) to 0 (in Pb).
Formula of the oxidizing agent: HPbO₂⁻
Formula of the reducing agent: Bi
收錄日期: 2021-04-18 14:40:58
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