HXeO4- + 2PH3 =Xe + 2P+ 3H2O+ OH- name element oxidized name element reduced formula oxidizing agent formula of the reducing agent?
回答 (1)
HXeO₄⁻ + 2PH₃ → Xe + 2P+ 3H₂O+ OH⁻
Name of the element oxidized : phosphorus
The oxidation number of P increases from -3 (in PH₃) to 0 (in P).
Name of the element reduced : xeon
The oxidation number of Xe decreases from +6 (in HXeO₄⁻) to 0 (in Xe).
Formula of the oxidizing agent : HXeO₄⁻
Formula of the reducing agent : PH₃
收錄日期: 2021-04-18 14:36:05
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