HXeO4- + 2PH3 =Xe + 2P+ 3H2O+ OH- name element oxidized name element reduced formula oxidizing agent formula of the reducing agent?

2016-03-17 10:29 am

回答 (1)

2016-03-17 11:35 am
HXeO₄⁻ + 2PH₃ → Xe + 2P+ 3H₂O+ OH⁻

Name of the element oxidized : phosphorus
The oxidation number of P increases from -3 (in PH₃) to 0 (in P).

Name of the element reduced : xeon
The oxidation number of Xe decreases from +6 (in HXeO₄⁻) to 0 (in Xe).

Formula of the oxidizing agent : HXeO₄⁻

Formula of the reducing agent : PH₃


收錄日期: 2021-04-18 14:36:05
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160317022942AA6UYVu

檢視 Wayback Machine 備份