A 0.150 M solution of a weak base has a pH of 9.55. What is the base hydrolysis constant, Kb, for the weak base? Please Chemistry Question?
回答 (1)
2016-03-17 12:53 am
✔ 最佳答案
Denote the weak base as B.B(aq) + H₂O(l) ⇌ HB⁺(aq) + OH⁻(aq)
At equilibrium :
pH = 9.55
pOH = 14 - 9.55 = 4.45
[OH⁻] = 10⁻⁴˙⁴⁵ M = 3.55 × 10⁻⁵ M
[HB⁺] = [OH⁻] = 3.55 × 10⁻⁵ M
[B] = (0.150 - 3.55 × 10⁻⁵) M ≈ 0.150 M
Kb = [HB⁺][OH⁻]/[B] = (3.55 × 10⁻⁵)²/0.150 = 8.4 × 10⁻⁹ (M)
收錄日期: 2021-04-18 14:35:55
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