1234567890/[1234567891^2-(1234567890*1234567892)]=?
回答 (2)
2016-03-13 1:43 pm
假設x=1234567891
則原式 =(x-1)[x^2-(x-1)(x+1)]
=(x-1)(x^2-x^2+1)
=(x-1)*1
=x-1=1234567890----Answer
則原式 =(x-1)[x^2-(x-1)(x+1)]
=(x-1)(x^2-x^2+1)
=(x-1)*1
=x-1=1234567890----Answer
2016-03-14 3:35 am
1234567890/[1234567891^2-(1234567890*1234567892)]
=1234567890/[1234567891^2-(1234567891-1)(1234567891+1)]
=1234567890/[1234567891^2-1234567891^2+1]
=1234567890
=1234567890/[1234567891^2-(1234567891-1)(1234567891+1)]
=1234567890/[1234567891^2-1234567891^2+1]
=1234567890
收錄日期: 2021-04-18 14:38:33
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160313034846AAklRcO