求Dxy
1.y=丌x的3次方 2.y=x(x平方+1)?
回答 (2)
y=丌x^3
y=x(x^2 +1)=x^3+x
丌x^3=x^3+x
(1-丌)x^3+x=0
x=0 or (1-丌)x^2+1=0
x=0 or (丌-1)x^2=1
x=0 or x=[1/(丌-1)]^0.5 or x=-[1/(丌-1)]^0.5
y=0 or x=[1/(丌-1)]^1.5 or x=-[1/(丌-1)]^1.5
收錄日期: 2021-04-18 14:36:24
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