求Dxy 1.y=丌x的3次方 2.y=x(x平方+1)?

2016-03-12 6:52 am

回答 (2)

2016-03-13 10:03 am
y=丌x^3
y=x(x^2 +1)=x^3+x
丌x^3=x^3+x
(1-丌)x^3+x=0
x=0 or (1-丌)x^2+1=0
x=0 or (丌-1)x^2=1
x=0 or x=[1/(丌-1)]^0.5 or x=-[1/(丌-1)]^0.5
y=0 or x=[1/(丌-1)]^1.5 or x=-[1/(丌-1)]^1.5
2016-03-12 2:07 pm
1. 30.959144x
2. 3x的2次方


收錄日期: 2021-04-18 14:36:24
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160311225236AAcIUwN

檢視 Wayback Machine 備份