急!! 求∫(1 to 2) (z^5*lnz) dz!!?
回答 (1)
2016-03-10 5:08 am
✔ 最佳答案
Key: ∫ uv' = uv - ∫ u'v∫(1 to 2) (z^5*lnz) dz u = ln(z) du = 1/z
v' = z^5 v = 1/6 * z^6
= (z^6 * lnz)/6 + ∫ (1/z)*(1/6 * z^6) dz
= [ (z^6 * lnz)/6 + (z^6)/36 ] (1 to 2)
= ( 32 ln (2) )/3 - 7/4
收錄日期: 2021-05-02 10:25:35
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160309202858AAJUhWi