∫ e^(2x+e^(2x))dx?
回答 (2)
2016-03-09 8:08 am
✔ 最佳答案
∫ e^[2x+e^(2x)] dx= ∫ e^(2x) e^[e^(2x)] dx
= (1/2) ∫ [2e^(2x)] e^[e^(2x)] dx
= (1/2) ∫ e^[e^(2x)] d[e^(2x)]
= (1/2) e^[e^(2x)] + C
2016-03-16 3:27 am
∫ e^[2x+e^(2x)] dx
= ∫ e^(2x) e^[e^(2x)] dx
= (1/2) ∫ [2e^(2x)] e^[e^(2x)] dx
= (1/2) ∫ e^[e^(2x)] d[e^(2x)]
= (1/2) e^[e^(2x)] + C
= ∫ e^(2x) e^[e^(2x)] dx
= (1/2) ∫ [2e^(2x)] e^[e^(2x)] dx
= (1/2) ∫ e^[e^(2x)] d[e^(2x)]
= (1/2) e^[e^(2x)] + C
收錄日期: 2021-04-18 14:43:32
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160308230847AA6nwwA