Chemistry help!?!?!?
2016-03-08 1:17 pm
5. A gas is initially under a pressure of 1140 mmHg. If the pressure is reduced to 0.94 atm and the new volume is measured to be 80 mL, what was the original volume of the gas?
回答 (1)
2016-03-08 1:27 pm
5.
P₁ = 1140 mmHg = 1140/760 atm, V₁ = ? mL
P₂ = 0.94 atm, V₂ = 80 mL
P₁V₁ = P₂V₂
Initial pressure, V₁
= P₂V₂/P₁
= 0.94 × 80 / (1140/760)
= 0.94 × 80 × (760/1140)
= 50 mL
P₁ = 1140 mmHg = 1140/760 atm, V₁ = ? mL
P₂ = 0.94 atm, V₂ = 80 mL
P₁V₁ = P₂V₂
Initial pressure, V₁
= P₂V₂/P₁
= 0.94 × 80 / (1140/760)
= 0.94 × 80 × (760/1140)
= 50 mL
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原文連結 [永久失效]:
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