improper integrals?

2016-03-08 10:34 am
determine int(-infinity to infinity) x/(1+x^2) dx is convergent or divergent

回答 (1)

2016-03-08 11:19 am
✔ 最佳答案
int(-infinity to infinity) x/(1+x^2) dx
=0.5int(-infinity to infinity)d(1+x^2) /(1+x^2)
=0.5In|1+x^2| |-infinity to infinity
=0.5In|1+infinity^2|-0.5In|1+(-infinity)^2|
=0


收錄日期: 2021-04-18 14:41:40
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