1. If a spring is stretched 2.0 cm by a suspending object having a mass of 0.55 kg, what is the spring constant of
the spring?
2. How much work is done by the spring on the object as it stretches through this distance?
i got 2.695 for 1 and 10.78 for 2
physics. Can you check my answers?
2016-03-05 5:45 am
回答 (1)
2016-03-05 4:28 pm
✔ 最佳答案
1. By Hooke: k = F / x = 0.55kg * 9.8m/s² / 0.020m = 270 N/mYou forgot to convert cm to m (or your units are N/cm, unorthodox)
2. W = ½kx² = ½ * 270N/m * (0.020m)² = 0.054 J = 54 mJ
As if you forgot the ½, and still have a units problem.
(Actually, the spring does negative work since the force is against the direction of motion.)
Hope this helps!
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