Chemistry help with gas laws??
2016-03-04 5:30 am
A balloon containing 0.5 L air at sea level is taken 10.0 m below the water where the pressure is 1520 mmHg, what is the balloon's new volume in mL?
回答 (2)
2016-03-04 5:52 am
✔ 最佳答案
At sea level : V₁ = 0.5 L, P₁ = 760 mmHgAt 10 m below the water : V₂ = ?, P₂ = 1520 mmHg
Under constant n and T, by Boyle's law :
P₁ V₁ = P₂ V₂
V₂ = P₁ V₁ / P₂ = 760 × 0.5 / 1520 L = 0.25 L = 250 mL
The balloon's new volume at 10 m below the water = 250 mL
2016-03-04 5:43 am
Seems like you'd use the equation P1V1 = P2V2 ['P' the value of pressure and 'V' for the value of volume] because temperature and gas are constant. However, there is no value given for the pressure of the balloon at sea level (verses 10m below the water). Maybe you accidentally excluded a value?
收錄日期: 2021-04-18 14:33:46
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