Challenging Exponential Questions?
If 60^a=3 and 60^b=5, then 12^((1-a-b)/(2(1-b)))=?
回答 (2)
60^a=3
a=(log 3)/(log 60)
60^b=5
b=(log 5)/(log 60)
12^((1-a-b)/(2(1-b)))
=12^((1-(log 3)/(log 60) -(log 5)/(log 60))/2(1-(log 5)/(log 60))))
=2
收錄日期: 2021-04-11 21:22:05
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