A 5.9 m uniform pole with a mass of 79 kg standing on its end. It is tipped 25◦
from the vertical and is starting to
rotate about the end that touches the ground. Find its angular acceleration
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2016-03-03 1:10 am
回答 (1)
2016-03-03 2:41 am
✔ 最佳答案
moment of inertiaI = mL²/3 = 79kg * (5.9m)² / 3 = 917 kg·m²
torque τ = r x F = m * g * (L/2) * sinΘ
τ = 79kg * 9.8m/s² * (5.9m/2) * sin25º = 965 N·m
But also τ = I*α, so
α = τ / I = 965N·m / 917kg·m² = 1.05 rad/s²
Hope this helps!
參考: Hey, was this one right?
https://answers.yahoo.com/question/index?qid=20160219152456AAxTbbB
Thanks for checking.
收錄日期: 2021-04-21 17:13:33
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160302171024AAZA2PF