1 mol of oxygen is heated at constant pressure of 1.00 atm from 10.0°C to 25.0°C. What is the change of volume of the gas in this process?
回答 (1)
2016-03-02 3:45 pm
PV = nRT
V = nRT/P
Volume before heating, V₁ = 1 × 0.0821 × (273 + 10.0) / 1 L
Volume after heating, V₁ = 1 × 0.0821 × (273 + 25.0) / 1 L
Change in volume of the gas, V₂ - V₁ = 0.0821 × (25.0 - 10.0) = 1.23 L
V = nRT/P
Volume before heating, V₁ = 1 × 0.0821 × (273 + 10.0) / 1 L
Volume after heating, V₁ = 1 × 0.0821 × (273 + 25.0) / 1 L
Change in volume of the gas, V₂ - V₁ = 0.0821 × (25.0 - 10.0) = 1.23 L
收錄日期: 2021-04-18 14:32:51
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