How many moles of H2 are needed to produce 10.60 g of NH3?
2016-03-02 5:39 am
please explain I seriously don't know how to do this or what the ratio has to do with it
回答 (1)
2016-03-02 6:58 am
Molar mass of NH₃ = 14.0 + 1.0×3 = 17.0 g/mol
No. of moles of NH₃ produced = 10.60/17.0 = 0.624 mol
N₂ + 3H₂ → 2NH₃
OR: Mole ratio H₂ : NH₃ = 3 : 2
No. of moles of H₂ needed = 0.624 × (3/2) = 0.936 mol
No. of moles of NH₃ produced = 10.60/17.0 = 0.624 mol
N₂ + 3H₂ → 2NH₃
OR: Mole ratio H₂ : NH₃ = 3 : 2
No. of moles of H₂ needed = 0.624 × (3/2) = 0.936 mol
收錄日期: 2021-04-18 14:37:07
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160301213935AAHVY98