integral x^2/3x-5 dx?

Please read :

i) By dividing it is: x/3 + 5/9 + 25/{9*(3x - 5)}

ii) Integrating, (1/6)*(x^2) + (5x/9) + (25/27)*ln|3x - 5| + C

X ^2 / 3 X ^-5 = X^2+5 / 3 = 1/3 X^7, integration of 1/3 x^7 = 1/3 * X^8/ 8 + X^7* 0 = X^8/24 + 0 = X^8/24