MATHS QUESTIONS!!!!!?

a)
K = (a + 1) / a
Ka = a + 1
Ka - a = 1
a (K - 1) = 1
a = 1 / (K - 1)


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b)
Case I :
K = (1/6)v(3a + v²)
6K = 3av + v³
3av = 6K - v³
a = (6K - v³) / (3v)

Case II :
K = [1/(6v)](3a + v²)
6Kv = 3a + v²
3a = 6Kv - v²
a = (6Kv - v²) / 3


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c)
Case I :
K=(1/5)v - (1/a)
1/a = (1/5)v - K
1/a = (v - 5K) / v
a = v / (v - 5K)

Case II :
K = [1/(5v)] - (1/a)
1/a = [1/(5v)] - K
1/a = (1 - 5Kv) / 5v
a = 5v / (1 - 5Kv)


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d)
k + 2=(3a + 1) / a
a (k + 2) = 3a + 1
ak + 2a = 3a + 1
3a - 2a = ak - 1
a = ak - 1

a)
k=(a+1)/a
ka=a+1
ak-a=1
a=1/(k-1)

b)
k=(1/6)v(3a+v^2)
6k=3av+v^3
3av=v^3-6k
a=(v^3-6k)/(3v)

c)
k=(1/5)v-1/a
k=(av-5)/(5a)
5ak=av-5
a=-5/(5k-v)

d)
k+2=(3a+1)/a
ak+2a=3a+1
a(k-1)=1
a=1/(k-1)