A loaded spring gun, initially at rest on a horizontal frictionless surface, fires a marble at an angle of elevation
θ. The mass of the gun is M, the mass of the marble is m, and the muzzle velocity of the marble is v0.
(a) What is the final horizontal velocity of the gun?
(b) What is the final horizontal velocity of the center of mass?
Studying for physics test?
2016-03-01 12:26 am
回答 (1)
2016-03-01 3:23 am
✔ 最佳答案
(a) M*V = m*v*cosΘfinal V = m*v*cosΘ / M
(b) No external horizontal forces are applied; the final horizontal velocity of the CM is zero.
Hope this helps!
收錄日期: 2021-04-21 17:10:32
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160229162631AA8SJNz