更新1:
This is the molecular formula: 1 PbSO4 (s) + 4 NaC2H3O2 (aq) 1 Na2[Pb(C2H3O2)4] (aq) + 1 Na2SO4 (aq)
Net ionic equation for lead(ii) sulfate + sodium acetate?
回答 (3)
2016-02-29 7:00 pm
If that is the correct molecular formula then the net ionic equation is
PbSO4(s) + 4C2H3O2^-(aq) ---> [Pb(C2H3O2)4]^2-(aq) + SO4^2-(aq)
for the formation of the complex ion
PbSO4(s) + 4C2H3O2^-(aq) ---> [Pb(C2H3O2)4]^2-(aq) + SO4^2-(aq)
for the formation of the complex ion
2016-02-29 6:34 pm
None. Lead(II) sulphate is already insoluble.
2016-02-29 6:39 pm
The reaction should be :
lead(II) acetate + sodium sulfate → lead(II) sulfate + sodium acetate
The net ionic equation is :
Pb²⁺(aq) + SO₄²⁻(aq) → PbSO₄(s)
lead(II) acetate + sodium sulfate → lead(II) sulfate + sodium acetate
The net ionic equation is :
Pb²⁺(aq) + SO₄²⁻(aq) → PbSO₄(s)
收錄日期: 2021-04-18 14:31:23
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160229103124AAgXBkw