Calculate the quantity of heat required to raise the temperature of 40.0 g of water from 21.3 °C to 38.0 °C?

👨🏻‍🏫 學術台化學

[匿名]

2016-02-29 8:48 am

回答 (1)

賣女孩的火柴

2016-02-29 9:24 am

m = 40.0 g
c = 4.18 g/°CK
ΔT = (38.0 - 21.3)°C

Heat required
= m c ΔT
= 40.0 × 4.18 × (38.0 - 21.3) J
= 2800 J
= 2.80 kJ

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