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√6-√(3/2)?
回答 (2)
2016-03-18 11:24 am
√6-√(3/2)
=√6-√(3/2)*√(2/2)
=√6-(√6)/2
=(2√6-√6)/2
=(√6)/2
=√6-√(3/2)*√(2/2)
=√6-(√6)/2
=(2√6-√6)/2
=(√6)/2
收錄日期: 2021-04-18 14:32:01
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160228225016AAfGsqd