1- No real solutions
2- {-5/2, 1/2}
3- -3 +/- 7 square root 2
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8
4- 3 +/- 7 square root 2
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8
Solve using the quadratic formula: 4x2 = -3x – 5?
2016-02-27 6:47 pm
回答 (4)
2016-02-27 6:59 pm
4x² = -3x - 5
4x² + 3x + 5 = 0
x = [-b ± √(b² - 4ac)] / 2a
x = [-3 ± √(3² - 4 × 4 × 5)] / (2 × 4)
x = [-3 ± √(-71)] / 8
x = [-3 + (√71)i] / 8 or x = [-3 + (√71)i] / 8
...... The answer is : 1 - no real solution
4x² + 3x + 5 = 0
x = [-b ± √(b² - 4ac)] / 2a
x = [-3 ± √(3² - 4 × 4 × 5)] / (2 × 4)
x = [-3 ± √(-71)] / 8
x = [-3 + (√71)i] / 8 or x = [-3 + (√71)i] / 8
...... The answer is : 1 - no real solution
2016-02-27 6:53 pm
So, what's your problem? a = 4 b = 3 and c = 5 plug in and solve.
2016-02-27 7:00 pm
not valid. Using AC = B, the values are not capable of finding the right numbers.
2016-02-27 6:58 pm
4x^2 - 3x - 5 = (3 +- sqrt(89)) / (8)
收錄日期: 2021-04-18 14:31:15
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