更新1:
A. 5/6 B. 1/216 C. 125/216 D. 215/216
When 3 dice are thrown, the probability of not getting any 2's is?
回答 (5)
2016-02-27 4:43 pm
The probability that a die roll is NOT a 2 is 5/6.
You have 3 independent dice, each with a probability of 5/6 of NOT rolling a two.
P(no twos) = 5/6 x 5/6 x 5/6
= 125/216
Answer:
C. 125/216
You have 3 independent dice, each with a probability of 5/6 of NOT rolling a two.
P(no twos) = 5/6 x 5/6 x 5/6
= 125/216
Answer:
C. 125/216
2016-02-27 4:42 pm
P(throw a die getting "2") = 1/6
P(throw a die not getting "2") = 5/6
P(throw 3 dices not getting a "2")
= P(1st die not getting "2") × P(2nd die not getting "2") × P(3rd die not getting "2")
= (5/6) × (5/6) × (5/6)
= 125/216
...... The answer is (C).
P(throw a die not getting "2") = 5/6
P(throw 3 dices not getting a "2")
= P(1st die not getting "2") × P(2nd die not getting "2") × P(3rd die not getting "2")
= (5/6) × (5/6) × (5/6)
= 125/216
...... The answer is (C).
2016-02-27 4:40 pm
(5/6) * (5/6) * (5/6) = 125/216
2016-02-27 4:45 pm
So the probability when throwing a die of getting a two is (1/6). The compliment of that probability (NOT getting a two) is 5/6. So the answer is (5/6)^3 or (5/6)(5/6)(5/6).
2016-02-27 4:43 pm
well there is 18 numbers all together becasue there are six numbers on each of the three die. the probablility of not rolling a two would be 5/6 so on three die it would be 15/18.
not 100% sure but yeah.
not 100% sure but yeah.
收錄日期: 2021-04-18 14:44:06
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