Raising temperature, chemistry?
回答 (1)
2016-02-26 4:24 pm
Amount of heat required
= m c ΔT
= (250 g) × (4.18 J/°Cg) × (56 - 20 °C)
= 37600 J
= 37.6 kJ
= m c ΔT
= (250 g) × (4.18 J/°Cg) × (56 - 20 °C)
= 37600 J
= 37.6 kJ
收錄日期: 2021-04-18 14:30:02
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https://hk.answers.yahoo.com/question/index?qid=20160226081952AAzHY65