Math logarithm problem?
回答 (2)
2016-02-26 3:52 pm
using:
logc(b)=logc(a)*loga(b)
and a^[loga(b)]=b
a^[logc(b)] = a^[logc(a)*loga(b)]
={a^[loga(b)]}^[logc(a)]
=b^[logc(a)]
logc(b)=logc(a)*loga(b)
and a^[loga(b)]=b
a^[logc(b)] = a^[logc(a)*loga(b)]
={a^[loga(b)]}^[logc(a)]
=b^[logc(a)]
收錄日期: 2021-04-18 14:32:23
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160226073042AAqImoG