Acetic acid (C2H4O2) is the active ingredient in vinegar. Calculate the mass percent composition of carbon in acetic acid??
回答 (1)
2016-02-26 3:11 pm
Mass of 1 mol of C₂H₄O₂ = 12×2 + 1×4 + 16×2 = 60 g
In1 mol of C₂H₄O₂, there are 2 mol of C.
Mass of C in 1 mol of C₂H₄O₂ = 12×2 = 24 g
Mass percent composition in C in C₂H₄O₂ = (24/60) × 100% = 40%
In1 mol of C₂H₄O₂, there are 2 mol of C.
Mass of C in 1 mol of C₂H₄O₂ = 12×2 = 24 g
Mass percent composition in C in C₂H₄O₂ = (24/60) × 100% = 40%
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