Physics question!!?

Take g = 9.81 m/s²

The motion of the bag sliding from the top to the bottom :
Time taken, t = 1.49 s
Distance, s = 2.60 m
Initial speed, u = 0 m/s
Acceleration, a = ? m/s²

s = u t + (1/2) a t²
2.60 = 0 + (1/2) × a × (1.49)²

Acceleration of the bag, a = 2.60 × 2 / (1.49)² = 2.34 m/s²


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The motion of the bag sliding from the top to the bottom :
Force, F = m g sin33.5° - f
Mass, m = 2.30 kg
Acceleration = 2.34 m/s²

F = m a
2.30 × 9.81 × sin33.5° - f = 2.30 × 2.34

Frictional force on the bag, f = 2.30 × 9.81 × sin33.5° - 2.30 × 2.34 = 7.07 N


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Normal force, N = m g cos33.5°
Frictional force, f = 7.07 N

Coefficient of kinetic friction between the bag and the slide
= f/N = 7.07 / (2.30 × 9.81 × cos33.5°)
= 0.376


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The motion of the bag sliding from the top to the bottom :
Time taken, t = 1.49 s
Distance, s = 2.60 m
Acceleration, a = 2.34 m/s²
Initial speed, u = 0 m/s
Final speed, v = ? m/s

v = u + at
v = 0 + 2.34 × 1.49
v = 3.49 m/s

Alternatively,
s = [(u + v)/2] t
2.60 = [(0 + v)/2] × 1.49
v = 2.60 × 2 / 1.49
v = 3.49 m/s

Speed of the bag when it reaches the bottom of the slide, v = 3.49 m/s