Let P(x) = F(x)G(x) and Q(x) = F(x)/G(x), where F and G are the functions whose graphs are shown.?

1)
When x = 2 :

F(2) = 3
The tangent is a horizontal line, and thus F'(2) = 0
G(2) = 2
G'(2) = the slope of the green going-up straight line = 2/4 = 1/2

P'(x) = F(x)G'(x) + F'(x)G(x)

Thus, P'(2)
= F(2)G'(2) + F'(2)G(2)
= 3 * (1/2) + 0 * 2
= 3/2


2)
When x = 7 :

F(7) = 5
F'(7) = slope of red straight line = 1/4
G(7) = 1
G'(7) = slope of the green going-down straight line = -2/3

P'(x) = F(x)G'(x) + F'(x)G(x)

Thus, P'(7)
= F(7)G'(7) + F'(7)G(7)
= 5 * (-2/3) + (1/4) * 1
= (-10/3) + (1/4)
= (-40/12) + (3/12)
= -37/12