Please solve: log4|3x+2|=3 ASAP.?
回答 (2)
2016-02-24 5:31 pm
Case 1 :
log₄|3x + 2| = 3
|3x + 2| = 4³
|3x + 2| = 64
3x + 2 = 64 or 3x + 2 = -64
3x = 62 or 3x = -66
x = 62/3 or x = -66
Case 2 :
log(4|3x + 2|) = 3
log₁₀(4|3x + 2|) = 3
4|3x + 2| = 10³
3x + 2 = 250 or 3x + 2 = -250
3x = 248 or 3x = -252
x = 248/3 or x = -84
log₄|3x + 2| = 3
|3x + 2| = 4³
|3x + 2| = 64
3x + 2 = 64 or 3x + 2 = -64
3x = 62 or 3x = -66
x = 62/3 or x = -66
Case 2 :
log(4|3x + 2|) = 3
log₁₀(4|3x + 2|) = 3
4|3x + 2| = 10³
3x + 2 = 250 or 3x + 2 = -250
3x = 248 or 3x = -252
x = 248/3 or x = -84
2016-02-24 5:50 pm
Is 4 the base of the logarithm, or part of the argument?
log₄|3x+2| = 3
|3x+2| = 4³ = 64
3x+2 = ±64
x = 62/3, -22
log₄|3x+2| = 3
|3x+2| = 4³ = 64
3x+2 = ±64
x = 62/3, -22
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