How do i simplify this rational expression? 10 pts?
回答 (4)
2016-02-24 7:48 am
[2a / (3 - a)] - [1 / 5(a + 2)]
= [2a × 5(a + 2) / 5(a + 2)(3 - a)] - [(3 - a) / 5(a + 2)(3 - a)]
= [(10a² + 20a) / 5(a + 2)(3 - a)] - [(3 - a) / 5(a + 2)(3 - a)]
= (10a² + 20a - 3 + a) / 5(a + 2)(3 - a)
= (10a² + 21a - 3) / 5(a + 2)(3 - a)
= [2a × 5(a + 2) / 5(a + 2)(3 - a)] - [(3 - a) / 5(a + 2)(3 - a)]
= [(10a² + 20a) / 5(a + 2)(3 - a)] - [(3 - a) / 5(a + 2)(3 - a)]
= (10a² + 20a - 3 + a) / 5(a + 2)(3 - a)
= (10a² + 21a - 3) / 5(a + 2)(3 - a)
2016-02-24 4:54 pm
( 2a / -a+3 ) - (1 / 5a +10)
2a - 1/ 4a + 13
2a - 1/ 4a + 13
2016-02-24 10:31 am
2a / [ 3 - a ] - 1 / [ 5 (a + 2) ]
2a (5a + 10) - (3 - a)
--------------------------------
5 ( 3 - a ) [a + 2 ]
10a² + 21a - 3
--------------------------
5 [ 3 - a] [a + 2 ]
2a (5a + 10) - (3 - a)
--------------------------------
5 ( 3 - a ) [a + 2 ]
10a² + 21a - 3
--------------------------
5 [ 3 - a] [a + 2 ]
2016-02-24 7:52 am
2a / (3-a) - 1 / 5(a+2) = [2a*5(a+2) - (3-a)] / 5(3-a)(a+2),
Or,
2a / (3-a) - 1 / 5(a+2) = [10a^2+20a -3 -a] / 5(3-a)(a+2),
Or,
2a / (3-a) - 1 / 5(a+2) = [10a^2 +19a -3] / 5(3-a)(a+2). >===========< ANSWER
Or,
2a / (3-a) - 1 / 5(a+2) = [10a^2+20a -3 -a] / 5(3-a)(a+2),
Or,
2a / (3-a) - 1 / 5(a+2) = [10a^2 +19a -3] / 5(3-a)(a+2). >===========< ANSWER
收錄日期: 2021-04-18 14:31:31
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20160223232654AA4kBO3