A 12.5 mL portion of a solution is diluted to 500mL and its molarity is determined to be .125?
回答 (1)
2016-02-24 6:13 am
Method 1 :
No. of moles of solute after dilution = 0.125 × (500/1000) = 0.0625 mol
No. of moles of solute before dilution = 0.0625 mol
Molarity of original solution = 0.0625 / (12.5/1000) = 5.00 M
Method 2 :
M₁V₁ = M₂V₂
Molarity of original solution, M₁ = M₂V₂/V₁ = 0.125 × 500 / 12.5 = 5.00 M
No. of moles of solute after dilution = 0.125 × (500/1000) = 0.0625 mol
No. of moles of solute before dilution = 0.0625 mol
Molarity of original solution = 0.0625 / (12.5/1000) = 5.00 M
Method 2 :
M₁V₁ = M₂V₂
Molarity of original solution, M₁ = M₂V₂/V₁ = 0.125 × 500 / 12.5 = 5.00 M
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