Find the y- intercept for the following. y=2^x+1 y=3^x+1 +2?
回答 (2)
2016-02-22 8:50 pm
At the y-intercept, x = 0
y = 2^x + 1
y = 2^0 + 1
y = 1 + 1
y = 2
Or did you mean:
y = 2^(x + 1)
y = 2^(0 + 1)
y = 2^1
y = 2
y = 3^x + 1 + 2
y = 3^x + 3
y = 3^0 + 3
y = 1 + 3
y = 4
Or did you mean:
y = 3^(x + 1) + 2
y = 3^(0 + 1) + 2
y = 3^1 + 2
y = 3 + 2
y = 5
y = 2^x + 1
y = 2^0 + 1
y = 1 + 1
y = 2
Or did you mean:
y = 2^(x + 1)
y = 2^(0 + 1)
y = 2^1
y = 2
y = 3^x + 1 + 2
y = 3^x + 3
y = 3^0 + 3
y = 1 + 3
y = 4
Or did you mean:
y = 3^(x + 1) + 2
y = 3^(0 + 1) + 2
y = 3^1 + 2
y = 3 + 2
y = 5
2016-02-22 8:45 pm
y=f(x)
the y- intercept = f(0)
the y- intercept = f(0)
收錄日期: 2021-04-21 17:07:16
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https://hk.answers.yahoo.com/question/index?qid=20160222124133AARNwTC