Find the y- intercept for the following. y=2^x+1 y=3^x+1 +2?

At the y-intercept, x = 0

y = 2^x + 1
y = 2^0 + 1
y = 1 + 1
y = 2
Or did you mean:
y = 2^(x + 1)
y = 2^(0 + 1)
y = 2^1
y = 2

y = 3^x + 1 + 2
y = 3^x + 3
y = 3^0 + 3
y = 1 + 3
y = 4
Or did you mean:
y = 3^(x + 1) + 2
y = 3^(0 + 1) + 2
y = 3^1 + 2
y = 3 + 2
y = 5

y=f(x)

the y- intercept = f(0)