What is the de Broglie wavelength of an electron traveling at 1.02×105 m/s ?
Express your answer with the appropriate units.
Chemistry help.. how to?
2016-02-22 6:31 pm
回答 (1)
2016-02-22 6:40 pm
Momentum = m v = h/λ
de Broglie wavelength, λ
= h / (m v)
= (6.626 × 10⁻³⁴) / [(9.109 × 10⁻³¹) × (1.02 × 10⁵)]
= 7.13 × 10⁻⁹ m
= 7.13 nm
de Broglie wavelength, λ
= h / (m v)
= (6.626 × 10⁻³⁴) / [(9.109 × 10⁻³¹) × (1.02 × 10⁵)]
= 7.13 × 10⁻⁹ m
= 7.13 nm
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